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log 2 (x) + log 2 (x-3) = 2. Solution: Using the product rule: log 2 (x∙(x-3)) = 2. Changing the logarithm form according to the logarithm definition: x∙(x-3) = 2 2. Or. x 2-3x-4 = 0. Solving the quadratic equation: x 1,2 = [3±√(9+16) ] / 2 = [3±5] / 2 = 4,-1. Since the logarithm is not defined for negative numbers, the answer is: x = 4 ... gmail google login